2y^2-3y^2+4y^2=

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Solution for 2y^2-3y^2+4y^2= equation:


Simplifying
2y2 + -3y2 + 4y2 = 0

Combine like terms: 2y2 + -3y2 = -1y2
-1y2 + 4y2 = 0

Combine like terms: -1y2 + 4y2 = 3y2
3y2 = 0

Solving
3y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '3'.
y2 = 0

Simplifying
y2 = 0

Take the square root of each side:
y = {0}

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